Algorithm
Leet Code Medium
[Swift] 4Sum
[Swift] 4Sum
Given an array nums
of n
integers, return an array of all the unique quadruplets [nums[a], nums[b], nums[c], nums[d]]
such that:
0 <= a, b, c, d < n
a, b, c,
andd
are distinct.nums[a] + nums[b] + nums[c] + nums[d] == target
You may return the answer in any order.
Example 1:
Input: nums = [1,0,-1,0,-2,2], target = 0
Output: [[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]
Example 2:
Input: nums = [2,2,2,2,2], target = 8
Output: [[2,2,2,2]]
Constraints:
- 1 <= nums.length <= 200
- $-10^9$ <= nums[i] <= $10^9$
- $-10^9$ <= target <= $10^9$
문제 이해
코드
func fourSum(_ nums: [Int], _ target: Int) -> [[Int]] {
if nums.count < 4 {
return []
}
var ret: Set<[Int]> = []
var nums = nums.sorted()
for a in 0 ..< nums.count - 3 {
for b in a + 1 ..< nums.count - 2 {
var c = b + 1
var d = nums.count - 1
while c < d {
let sum = nums[a] + nums[b] + nums[c] + nums[d]
if sum == target {
ret.insert([nums[a], nums[b], nums[c], nums[d]])
}
if sum < target {
c += 1
} else {
d -= 1
}
}
}
}
return ret.map { Array($0) }
}
풀이
-
다른 분의 멋진 코드
잘 배웠습니다.
-
댓글남기기